“Five Easy Pieces” problem
I’ve
posted on the Retros mailing list, December 27th, 2009, this “problem with an incomplete diagram” (please
forgive again my bad English):
> Hello RetroFans,
16+16 C+(Euclide)
Remove 5 white
pieces that are placed
on same-colour squares and reach the new
position in
11.0 moves.
(example of a possible removal : Ra1,
b2, Bc1, d2 and
f2, were on dark squares)
11+16
Which are the 5
white pieces you'll
have to remove
from the chessboard in
order to
complete the above task?
Best,
É.
---
The answer is further down.
Remove Nb1, Qd1, e2, Bf1, g2
11+16
This position can be reached in 11.0 moves (the
path is NOT unique):
(1)e4 c6 (2)Ba6
NxB (3)Qf3 Nb8 (4)Qf6
exQ (5)e5 Bd6 (6)Nc3
Bc7 (7)Ne4 d6 (8)g4 Bxg4 (9)Ng5 Bh5 (10)e6 fxe6 (11)Nf7 BxN
I guess this is the only removal of Five-White-Pieces-of-the-same-colour-square allowing the players to achieve the task.
Best,
É.
_________
Nicolas Dupont mentions this pb here (in French):
http://www.france-echecs.com/index.php?mode=showComment&art=20091228181321915
I’ve received this nice comment from Mario R. on December 29th 2009:
> Your new
challenge "Five White pieces, same square-colour"
was also interesting.
It shows an
unusual asymmetric effect: on white squares, you have the choice between 8
pieces, on dark squares only between 7 pieces.
Furthermore, on
dark squares, the removal of pawns might expose the wK
to diagonal checks, while on white squares this is not possible (of course only
if the wK doesn't move).
>> I guess
this is the only removal of Five-White-Pieces-of-the-same-colour-square
>> allowing
the players to achieve the task.
There is no need
for guess work here: there are only 56+21 positions to investigate, and that's
not really a hurdle for 'natch' or 'Euclide'.
I used the latter
to validate, that only the removal of (Pe2,Pg2,Nb1,Qd1,Bf1)
fulfills the conditions of the stipulation.
So you can mark
your problem as "C+" (Euclide).
Thanks, Mario
-- done!